2[t-(2t+15)+10]=2(t+5)

Solution for 2[t-(2t+15)+10]=2(t+5) equation:

Simplifying
2[t + -1(2t + 15) + 10] = 2(t + 5)

Reorder the terms:
2[t + -1(15 + 2t) + 10] = 2(t + 5)
2[t + (15 * -1 + 2t * -1) + 10] = 2(t + 5)
2[t + (-15 + -2t) + 10] = 2(t + 5)

Reorder the terms:
2[-15 + 10 + t + -2t] = 2(t + 5)

Combine like terms: -15 + 10 = -5
2[-5 + t + -2t] = 2(t + 5)

Combine like terms: t + -2t = -1t
2[-5 + -1t] = 2(t + 5)
[-5 * 2 + -1t * 2] = 2(t + 5)
[-10 + -2t] = 2(t + 5)

Reorder the terms:
-10 + -2t = 2(5 + t)
-10 + -2t = (5 * 2 + t * 2)
-10 + -2t = (10 + 2t)

Solving
-10 + -2t = 10 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-10 + -2t + -2t = 10 + 2t + -2t

Combine like terms: -2t + -2t = -4t
-10 + -4t = 10 + 2t + -2t

Combine like terms: 2t + -2t = 0
-10 + -4t = 10 + 0
-10 + -4t = 10

Add '10' to each side of the equation.
-10 + 10 + -4t = 10 + 10

Combine like terms: -10 + 10 = 0
0 + -4t = 10 + 10
-4t = 10 + 10

Combine like terms: 10 + 10 = 20
-4t = 20

Divide each side by '-4'.
t = -5

Simplifying
t = -5